Rightmost Digit

浏览数：12 / 时间：2015年06月09日

Rightmost Digit

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 35128 Accepted Submission(s): 13337

Problem Description

Given a positive integer N, you should output the most right digit of N^N.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).

Output

For each test case, you should output the rightmost digit of N^N.

Sample Input

2
3
4

Sample Output

7
6

Hint

In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7.
In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.

解题思路：找规律，通过程序找出规律，即周期=20；循环节为{0,1,4,7,6,5,6,3,6,9,0,1,6,3,6,5,6,7,4,9,0}
源代码：
#include <stdio.h>
#include <stdlib.h>
int main()
{
  int a[21]={0,1,4,7,6,5,6,3,6,9,0,1,6,3,6,5,6,7,4,9,0};
  int t,n;
  scanf("%d",&t);
  while(t--)
  {
    scanf("%d",&n);
    printf("%d\n",a[n%20]);          
  }
  system("pause");
  return 0;    
}

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Rightmost Digit