HttpWebRequest 返回BadRequest(400) 同时返回Response

浏览数：54 / 时间：2015年06月09日

今天用Fiddler分析安卓APP的一个登陆功能的时候，账号和密码错误会返回相应的消息，并且状态码是400。

正常用法：

 1         /// <summary>
 2         /// 读取返回的内容
 3         /// </summary>
 4         /// <param name="asyncresult"></param>
 5         private void ReadCallBack(IAsyncResult asyncresult)
 6         {
 7             String result = String.Empty;
 8             try
 9             {
10                 HttpWebRequest myrequest = (HttpWebRequest)asyncresult.AsyncState;
11                 HttpWebResponse response = (HttpWebResponse)myrequest.EndGetResponse(asyncresult);
12 
13                 //读取返回对象
14                 Stream responseStream = response.GetResponseStream();
15 
16                 using (var render = new StreamReader(responseStream, Encoding.UTF8))
17                 {
18                     result = render.ReadToEnd();
19                     render.Close();
20                 }
21             }
22             catch (Exception ex)
23             {
24 
25                 Console.WriteLine("出现异常：" + ex.Message);
26             }
27             //处理返回消息
28             if (Handler != null)
29                 Handler(result);
30         }

当执行GetResponseStream就抛出异常了，异常提示是BadRequest.

要想获取400返回的信息，需要对catch部分做特殊处理。

添加catch代码：

 1                 using (WebResponse response = e.Response)
 2                 {
 3                     HttpWebResponse httpResponse = (HttpWebResponse)response;
 4                     using (Stream data = response.GetResponseStream())
 5                     using (var reader = new StreamReader(data))
 6                     {
 7                         string text = reader.ReadToEnd();
 8                         Console.WriteLine(text);
 9                     }
10                 }